72x+36x^2=0

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Solution for 72x+36x^2=0 equation:



72x+36x^2=0
a = 36; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·36·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*36}=\frac{-144}{72} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*36}=\frac{0}{72} =0 $

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